x2 = x^2
here short form
x2-xy-xz-2xy+2yz+2y2+xz-yz-z2
= x(x-y-z)-2y(x-y-z)+z(x-y-z)
=(x-y-z)(x-2y+z)
correction!
sry...pmr o6 de 2 careless mistake
thx alvin n xin
alvin
for UEC de obj
dita =y
x=y
y=v
y=z
so dita=x y z v
dita nt = w
lol no.20
sry alvin y=45
x=100
so x+y=145
sry
thx alvin n xin
alvin
for UEC de obj
dita =y
x=y
y=v
y=z
so dita=x y z v
dita nt = w
lol no.20
sry alvin y=45
x=100
so x+y=145
sry
UEC 07 paper 2
due to many ppl request
i juz teach sum question
1(b)
all chg to 假分数
den can约简
answer is 50
1(d)
tis question 3 marks
actually
i dunnoe the proper way to solve tis
bt hope u understand wad i am talking
3p - 5q =31
p是质数
此质数x3后,31减这个号码
剩下的一定要是5的倍数
here is the tips..
den u try solve
thx
4(b)
x + 1/x= -1
(x+1/x)^3 = x^3 +3x^2(1/x) + 3x(1/x)^2 + 1/x^3
-1= x^3 + 1/x^3 + 3x^2/x + 3x/x^2
-1= x^3 + 1/x^3 + 3x + 3(1/x)
= x^3 + 1/x^3 + 3(x+1/x)
= x^3 + 1/3^3 +3(-1)
= x^3 + 1/3^3 -3
x^3 + 1/3^3 = 2
if still hav problem leave a comment here
i juz teach sum question
1(b)
all chg to 假分数
den can约简
answer is 50
1(d)
tis question 3 marks
actually
i dunnoe the proper way to solve tis
bt hope u understand wad i am talking
3p - 5q =31
p是质数
此质数x3后,31减这个号码
剩下的一定要是5的倍数
here is the tips..
den u try solve
thx
4(b)
x + 1/x= -1
(x+1/x)^3 = x^3 +3x^2(1/x) + 3x(1/x)^2 + 1/x^3
-1= x^3 + 1/x^3 + 3x^2/x + 3x/x^2
-1= x^3 + 1/x^3 + 3x + 3(1/x)
= x^3 + 1/x^3 + 3(x+1/x)
= x^3 + 1/3^3 +3(-1)
= x^3 + 1/3^3 -3
x^3 + 1/3^3 = 2
if still hav problem leave a comment here
answer for UEC 07
same...tis mayb mur mistake
nt going to write all
juz sum question
3)D
*every number which isnt 质数,is 合数
11)B
15)B
* dunnoe ask here
18)B
20)C
21)D
23)A
*把pai抽出来
RxR-rxr=33
R是大圆的半径
r是小圆的半径
29)B
log2 x=0.66
log2 y=1.68
tat means
2的0.66次方=x
2的1.68次方=y
37)E
平方式来的
nt going to write all
juz sum question
3)D
*every number which isnt 质数,is 合数
11)B
15)B
* dunnoe ask here
18)B
20)C
21)D
23)A
*把pai抽出来
RxR-rxr=33
R是大圆的半径
r是小圆的半径
29)B
log2 x=0.66
log2 y=1.68
tat means
2的0.66次方=x
2的1.68次方=y
37)E
平方式来的
answer for PMR 06 obj
erm...answer 99% correct onli
i din double check
so if detect any error plz leave a comment
thx
D C A C
A C D A
B D B D
A C C B
B D C C
C A A C
C A B C
C D B B
A A C D
B B D B
i din double check
so if detect any error plz leave a comment
thx
D C A C
A C D A
B D B D
A C C B
B D C C
C A A C
C A B C
C D B B
A A C D
B B D B
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