UEC 07 paper 2

due to many ppl request
i juz teach sum question

1(b)
all chg to 假分数
den can约简
answer is 50

1(d)
tis question 3 marks
actually
i dunnoe the proper way to solve tis
bt hope u understand wad i am talking
3p - 5q =31
p是质数
此质数x3后，31减这个号码
剩下的一定要是5的倍数
here is the tips..
den u try solve
thx

4(b)
x + 1/x= -1
(x+1/x)^3 = x^3 +3x^2(1/x) + 3x(1/x)^2 + 1/x^3
-1= x^3 + 1/x^3 + 3x^2/x + 3x/x^2
-1= x^3 + 1/x^3 + 3x + 3(1/x)
= x^3 + 1/x^3 + 3(x+1/x)
= x^3 + 1/3^3 +3(-1)
= x^3 + 1/3^3 -3
x^3 + 1/3^3 = 2

if still hav problem leave a comment here